In order to get a list of all tables in the current database, you can filter the sysobjects table by type = ‘U’ e.g.:

select convert(varchar(30),o.name) AS table_name
from sysobjects o
where type = 'U'
order by table_name

In order to get the number of rows of each table, you can use the row_count function. It takes two arguments:

• the database ID – you can get the ID of the current database using the db_id function
• the object ID – it’s the id column in sysobjects

e.g.:

select convert(varchar(30),o.name) AS table_name,
row_count(db_id(), o.id) AS row_count
from sysobjects o
where type = 'U'
order by table_name

And in order to get some size information you can use the data_pages function. It will return the number of pages and you can then multiply it by the number of kilobyte per page e.g.:

select convert(varchar(30),o.name) AS table_name,
row_count(db_id(), o.id) AS row_count,
data_pages(db_id(), o.id, 0) AS pages,
data_pages(db_id(), o.id, 0) * (@@maxpagesize/1024) AS kbs
from sysobjects o
where type = 'U'
order by table_name

The first column returned by this statement contains the table name (if you have names longer than 30 characters, you should replace 30 by something higher), the number of rows, the number of data pages, the size in kilobytes.

If you have an ASE version older than 15, the statement above will not work but you can use the statement below instead:

select sysobjects.name,
Pages = sum(data_pgs(sysindexes.id, ioampg)),
Kbs = sum(data_pgs(sysindexes.id, ioampg)) * (@@maxpagesize/1024)
from sysindexes, sysobjects
where sysindexes.id = sysobjects.id
    and sysindexes.id > 100
    and (indid > 1)
group by sysobjects.name
order by sysobjects.name

This will return the table name, number of pages and size in kilobytes.